document.write( "Question 662642: A two-digit number has 3 in its unit digit. The sum of its digits is one-seventh of the number itself. What is the number? \n" ); document.write( "
Algebra.Com's Answer #412414 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
Sorry, thought I could cut corners and give you the quick answer. Here's the whole story.
\n" ); document.write( "Let n = tens digit
\n" ); document.write( "Let m = units digit
\n" ); document.write( "Then your whole number is
\n" ); document.write( "(1) N = 10*n + m, agree?
\n" ); document.write( "Now you tell me that the sum of the two digits is 1/7th of N or
\n" ); document.write( "(2) n + m = 1/7*(10*n + m)
\n" ); document.write( "You also tell me that the units digit is 3 or
\n" ); document.write( "(3) m = 3
\n" ); document.write( "Now to solve, put (3) into (2) and get
\n" ); document.write( "(4) n + 3 = 1/7*(10*n + 3) or
\n" ); document.write( "(5) 7*n + 21 = 10*n + 3, where I simply multiplied both sides by 7.
\n" ); document.write( "or
\n" ); document.write( "(6) 3*n = 18 or
\n" ); document.write( "(7) n = 6
\n" ); document.write( "Therefore your number is from (1)
\n" ); document.write( "(8) N = 10*6 + 3 or
\n" ); document.write( "(9) N = 63, voila! The wizard strikes again. lol\r
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