document.write( "Question 662639: Find an equation of a straight line through the point P (2, 3) and parallel to line 3x+5y=10 \n" ); document.write( "
Algebra.Com's Answer #412413 by DrBeeee(684)\"\" \"About 
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You need to find the slope of the given line
\n" ); document.write( "(1) 3x + 5y = 10 which is given in the standard form
\n" ); document.write( "(2) Ax + By = C whose slope is given by
\n" ); document.write( "(3) m = -A/B which, for the given line, yields
\n" ); document.write( "(4) m = -3/5.
\n" ); document.write( "To be parallel to this line, the new line must have the same slope. In the slope-intercept form we want
\n" ); document.write( "(5) y = -3/5x + b.
\n" ); document.write( "We deterine the value of b by satisfying the second condition that it must pass through P(2,3). Substituting P into (5) yields
\n" ); document.write( "(6) 3 = -3/5(2) + b
\n" ); document.write( "Solve (6) for b gives
\n" ); document.write( "(7) b = 21/5
\n" ); document.write( "Your new line is
\n" ); document.write( "(8) y = -(3/5)x + 21/5
\n" ); document.write( "Let's use P(2,3) to check the equation.
\n" ); document.write( "Is (3 = -(3/5)*2 + 21/5)?
\n" ); document.write( "Is (3 = -6/5 + 21/5)?
\n" ); document.write( "Is (3 = 15/5)?
\n" ); document.write( "Is (3 = 3)? Yes
\n" ); document.write( "Answer: The new line is y = -(3/5)x + 21/5 \n" ); document.write( "
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