document.write( "Question 662591: find the area and perimeter or circumference of:
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document.write( "Rectangle of L = 8 and W = 1/4 L in feet
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document.write( "Area = L x W = 200\r
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document.write( "perimeter 2L + 2W = L =8+8 W = 25+25 = 66sq ft \n" );
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Algebra.Com's Answer #412399 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! find the area and perimeter or circumference of: \n" ); document.write( "Rectangle of L = 8 and W = 1/4 L in feet \n" ); document.write( "Area = L x W = 200 \n" ); document.write( "====================== \n" ); document.write( "If L = 8 and W = (1/4)L, then W = 2 \n" ); document.write( "Area = 16 \n" ); document.write( "P = 20\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |