document.write( "Question 662517: Find three consecutive multiples of seven such that the product of the largest two exceeds the product of the smallest two by one thousand and seventy-eight \n" ); document.write( "
Algebra.Com's Answer #412392 by ankor@dixie-net.com(22740)\"\" \"About 
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Find three consecutive multiples of seven such that the product of the largest two exceeds the product of the smallest two by one thousand and seventy-eight
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\n" ); document.write( "Let x = the middle multiple of 7
\n" ); document.write( "then
\n" ); document.write( "(x-7), x, (x+7) are the three consecutive multiples of 7
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\n" ); document.write( "\" the product of the largest two exceeds the product of the smallest two by one thousand and seventy-eight
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\n" ); document.write( "x(x+7) - x(x-7) = 1078
\n" ); document.write( "(x^2 + 7x) - (x^2-7x) = 1078
\n" ); document.write( "combine like terms, after removing the brackets
\n" ); document.write( "x^2 - x^2 + 7x + 7x = 1078
\n" ); document.write( "14x = 1078
\n" ); document.write( "x = 1078/14
\n" ); document.write( "x = 77 is the middle multiple
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\n" ); document.write( "70, 77, 84 are the three multiples
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\n" ); document.write( "see if that flies
\n" ); document.write( "(84*77) - 70*77) = 1078
\n" ); document.write( "6468 - 5390 = 1078 \n" ); document.write( "
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