document.write( "Question 662623: the denominators of a fraction is 1 more than the numerator if the numerator is doubled while the denominator remain the same the sum of this fraction and the original one is 2 find the fraction? \n" ); document.write( "

Algebra.Com's Answer #412390 by mananth(16946) $\"\"$ $\"About$

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let numerator be x
\n" ); document.write( "denominator = x+1\r
\n" ); document.write( "\n" ); document.write( "Numerator doubled = 2x
\n" ); document.write( "denominator = x+1\r
\n" ); document.write( "\n" ); document.write( " $\"%28x%2F%28x%2B1%29%29+%2B+%282x%2F%28x%2B1%29%29+=2\"$ \r
\n" ); document.write( "\n" ); document.write( "LCD = (x+1)\r
\n" ); document.write( "\n" ); document.write( " $\"3x%2F%28x%2B1%29\"$ = 2\r
\n" ); document.write( "\n" ); document.write( "3x=2(x+1)
\n" ); document.write( "3x=2x+2
\n" ); document.write( "3x-2x=1
\n" ); document.write( "x=2
\n" ); document.write( "denominator = x+1 = 1+2 =3
\n" ); document.write( "The fraction is 2/3\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "

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