document.write( "Question 662617: Hello, I am a year 10 student and need help with the following solution:\r
\n" ); document.write( "\n" ); document.write( "Can you please help me with this solution:
\n" ); document.write( "2x²+10x+12=0\r
\n" ); document.write( "\n" ); document.write( "This is what I tried:
\n" ); document.write( "I divided the 10 and the 12 by the 2 that is shown at the start of the equation and i moved the x² of that 2 into the bracket. It looked liked this:
\n" ); document.write( "2(x+5x+6)=0
\n" ); document.write( "The 5x was from the 10, i divided the 10 by 2 and then i divided the 12 by 2 and i got 6.
\n" ); document.write( "I am unaware if i got this first step correct, if so can you please help me with the rest and if not can you please help me with the whole question. \r
\n" ); document.write( "\n" ); document.write( "Kind regards Holly, thank-you.\r
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Algebra.Com's Answer #412381 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
Starting with
\n" ); document.write( "2x^2 + 10x + 12 =0
\n" ); document.write( "Factor out the 2
\n" ); document.write( "2(x^2 + 5x + 6) = 0
\n" ); document.write( "2(x+ )(x+ )both addition signs due to positive 5 and positive 6
\n" ); document.write( "consider multiple of 6 which will add up to 5
\n" ); document.write( "2(x+3)(x+2)=0
\n" ); document.write( "divide both sides by 2
\n" ); document.write( "(x+3)(x+2)=0
\n" ); document.write( "x+3=0, so x=-3
\n" ); document.write( "x+2=0, so x=-2
\n" ); document.write( ".................
\n" ); document.write( "Delighted to help.
\n" ); document.write( "-Reading Boosters
\n" ); document.write( "What we want for others what we want for ourselves.
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