document.write( "Question 662548: a total of 15600 was invested between two accounts: one paying 4% simple interest and the other paying 3% simple interest. after 1 year the total interest was $490. how much was invested? \n" ); document.write( "
Algebra.Com's Answer #412364 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! 0.04x+0.03(15600-x=490 \n" ); document.write( "0.04x+468-0.03x=490 \n" ); document.write( "0.01x=490-468 \n" ); document.write( "0.01x=22 \n" ); document.write( "x=22/0.01 \n" ); document.write( "x=2200 at 4% \n" ); document.write( "15600-2200=13400 at 3% \n" ); document.write( " |