document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=662578>Question 662578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for triangle missing side b, missing bottom a, other side 6 with 2 angles both @ 45 degrees. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412358 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 2 angles at 45 degrees is the key hint for the right triangle with a 1,1 sqrt(2) pattern.<BR>\n" );
document.write( "Knowing a^2+b^2=c^2, then c^2 = 36<BR>\n" );
document.write( "a and b are the same, so<BR>\n" );
document.write( "a^2 + a^2 = 36<BR>\n" );
document.write( "2a^2 = 36<BR>\n" );
document.write( "divide both sides by 2<BR>\n" );
document.write( "a^2 = 18<BR>\n" );
document.write( "a = sqrt(18)<BR>\n" );
document.write( "b = sqrt(18)<BR>\n" );
document.write( "c = 6<BR>\n" );
document.write( "......................<BR>\n" );
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document.write( "-Reading Boosters<BR>\n" );
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