document.write( "Question 662527: A chemist needs 7 liters of a 50% salt solution. All she has is a 20% salt solution and a 70% salt solution. How much of each of the two solutions should she mix to obtain her desired solution? \n" ); document.write( "
Algebra.Com's Answer #412331 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+a+\" = liters of 20% solution needed
\n" ); document.write( "Let \"+b+\" = liters of 70% solution needed
\n" ); document.write( "-----------
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+a+%2B+b+=+7+\"
\n" ); document.write( "(2) \"+%28+.2a+%2B+.7b+%29+%2F+7+=+.5+\"
\n" ); document.write( "------------------------
\n" ); document.write( "(2) \"+.2a+%2B+.7b+=+.5%2A7+\"
\n" ); document.write( "(2) \"+2a+%2B+7b+=+35+\"
\n" ); document.write( "Multiply both sides of (1) by \"2\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+2a+%2B+7b+=+35+\"
\n" ); document.write( "(1) \"+-2a+-+2b+=+-14+\"
\n" ); document.write( "\"+5b+=+21+\"
\n" ); document.write( "\"+b+=+21%2F5+\"
\n" ); document.write( "\"+b+=+4.2+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+a+%2B+b+=+7+\"
\n" ); document.write( "(1) \"+a+%2B+b+=+35%2F5+\"
\n" ); document.write( "(1) \"+a+%2B+21%2F5+=+35%2F5+\"
\n" ); document.write( "(1) \"+a+=+14%2F5+\"
\n" ); document.write( "(1) \"+a+=+2.8+\"
\n" ); document.write( "2.8 liters of 20% solution is needed
\n" ); document.write( "4.2 liters of 70% solution is needed
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.2a+%2B+.7b+%29+%2F+7+=+.5+\"
\n" ); document.write( "(2) \"+%28+.2%2A2.8+%2B+.7%2A4.2+%29+%2F+7+=+.5+\"
\n" ); document.write( "(2) \"+%28+.56+%2B+2.94+%29+%2F+7+=+.5+\"
\n" ); document.write( "(2) \"+3.5+%2F+7+=+.5+\"
\n" ); document.write( "(2) \"+3.5+=+.5%2A7+\"
\n" ); document.write( "(2) \"+3.5+=+3.5+\"
\n" ); document.write( "OK\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );