document.write( "Question 662521: A man is 32 years older than his son. Ten years ago he was three times as old as his son was then. Find the present age of each. \n" ); document.write( "
Algebra.Com's Answer #412329 by josmiceli(19441)\"\" \"About 
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Let \"+f+\" = Father's age
\n" ); document.write( "Let \"+s+\" = Son's age
\n" ); document.write( "given:
\n" ); document.write( "\"+f+=+s+%2B+32+\"
\n" ); document.write( "\"+f+-+10+=+3%2A%28+s+-+10+%29+\"
\n" ); document.write( "----------------------
\n" ); document.write( "By substitution:
\n" ); document.write( "\"+s+%2B+32+-+10+=+3s+-+30+\"
\n" ); document.write( "\"+2s+=+32+%2B+30+-+10+\"
\n" ); document.write( "\"+2s+=+52+\"
\n" ); document.write( "\"+s=+26+\"
\n" ); document.write( "and, since
\n" ); document.write( "\"+f+=+s+%2B+32+\"
\n" ); document.write( "\"+f+=+26+%2B+32+\"
\n" ); document.write( "\"+f+=+58+\"
\n" ); document.write( "The Father is 58
\n" ); document.write( "The Son is 26
\n" ); document.write( "check:
\n" ); document.write( "\"+f+-+10+=+3%2A%28+s+-+10+%29+\"
\n" ); document.write( "\"+58+-+10+=+3%2A%28+26+-+10+%29+\"
\n" ); document.write( "\"+48+=+3%2A16+\"
\n" ); document.write( "\"+48+=+48+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );