document.write( "Question 662502: You find 8 coins in an old desk drawer, consisting entirely of nickels, dimes, and quarters, with a face value of 80 cents. However, the coins all date from 1889 and are worth much more than their face value. You were able to sell all the coins to a coin shop for a total of $22. Suppose you received $3 for each nickel, $2 for each dime, and $5 for each quarter. How many of the coins were quarters? \n" ); document.write( "
Algebra.Com's Answer #412313 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the number of nickels, represent the number of dimes, and represent the number of quarters.\r
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\n" ); document.write( "\n" ); document.write( "because the total number of coins is 8\r
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\n" ); document.write( "\n" ); document.write( "because the total FACE value of the coins is 80 cents, each nickel is worth 5 cents, each dime is worth 10 cents, and each quarter is worth 25 cents.\r
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\n" ); document.write( "\n" ); document.write( "because the total SALE value of the coins is 22 dollars, each nickel is worth 3 dollars, each dime is worth 2 dollars, and each quarter is worth 5 dollars.\r
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\n" ); document.write( "\n" ); document.write( "Solve the 3X3 system. Report the value of \r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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