document.write( "Question 662459: This question was answered, but the answer confused me even more - So I will enter the Table we are to use also then maybe you folks can help unconfuse me.
\n" ); document.write( "Problem: If we wish to have a 99% confidence interval, what would be the value of the confidence coefficient, z(a/2)? (Use Table 4B)
\n" ); document.write( "Table 4B:
\n" ); document.write( "a.....0.25...0.20...0.10...0.05...0.02...0.01
\n" ); document.write( "z(a/2..1.15...1.28..1.65...1.96...2.33...2.58
\n" ); document.write( "1-a....0.75...0.80..0.90...0.95...0.98...0.99
\n" ); document.write( "

Algebra.Com's Answer #412305 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "certainly can understand Your diligence...
\n" ); document.write( "\"1-.01%2F2+=+.995\"translating .995 to a z-value gives 2.58
\n" ); document.write( "Table 4B:
\n" ); document.write( " a.....0.25...0.20...0.10...0.05...0.02...0.01 Percents listed as decimals
\n" ); document.write( "z(a/2)..1.15...1.28..1.65...1.96...2.33...\"highlight%282.58%29\"
\n" ); document.write( " 1-a....0.75...0.80..0.90...0.95...0.98...0.99 Percents listed as decimals
\n" ); document.write( " 1-a/2....0.875...0.90..0.95...0.975...0.99...0.995 and NORMSDIST(.995) = 2.58 \n" ); document.write( "
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