document.write( "Question 662476: Please help me figure out the formula to complete the following question: The sum of two numbers is 17. If twice the small number is 1 more than the larger number, find the numbers. \n" ); document.write( "

Algebra.Com's Answer #412281 by ReadingBoosters(3246) $\"\"$ $\"About$

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set the variables
\n" ); document.write( "x=smaller number
\n" ); document.write( "y=larger number
\n" ); document.write( "x+y=17
\n" ); document.write( "2x=1+y
\n" ); document.write( "Solve one of two ways
\n" ); document.write( "..
\n" ); document.write( "Option 1
\n" ); document.write( "2(x+y=17)
\n" ); document.write( "2x+2y=34 and plug in 2x
\n" ); document.write( "1+y+2y=34
\n" ); document.write( "using y, plug into x=17-y to solve for x
\n" ); document.write( "OR solve by
\n" ); document.write( "..
\n" ); document.write( "Option2
\n" ); document.write( "2x=1+y
\n" ); document.write( "x=1/2 + y/2 and plug in to x+y=17
\n" ); document.write( "(1/2 + y/2)+y=17
\n" ); document.write( "using y, plug into x=17-y to solve for y
\n" ); document.write( "..
\n" ); document.write( "Personally, I think option 1 is an easier and cleaner formula to solve
\n" ); document.write( "using y, plug into x=17-y to solve for x
\n" ); document.write( "..........................
\n" ); document.write( "Delighted to help.
\n" ); document.write( "-Reading Boosters
\n" ); document.write( " \n" ); document.write( "

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