document.write( "Question 662445: A list contains 11 consecutive integers. If x is the smallest integer and y is the greatest integer on the list, and 16x^-2=y^-2. Find the value of (x+y)? \n" ); document.write( "
Algebra.Com's Answer #412271 by Edwin McCravy(20062) You can put this solution on YOUR website! \r\n" ); document.write( "The list of 11 consists of\r\n" ); document.write( "\r\n" ); document.write( "1. x\r\n" ); document.write( "2. x+1\r\n" ); document.write( "3. x+2\r\n" ); document.write( "4. x+3\r\n" ); document.write( "5. x+4\r\n" ); document.write( "6. x+5\r\n" ); document.write( "7. x+6\r\n" ); document.write( "8. x+7\r\n" ); document.write( "9. x+8\r\n" ); document.write( "10. x+9\r\n" ); document.write( "11. x+10\r\n" ); document.write( "\r\n" ); document.write( "So x is the the smallest and y = x+10 is the largest.\r\n" ); document.write( "\r\n" ); document.write( "16x-2 = y-2\r\n" ); document.write( "\r\n" ); document.write( "Using the definition of negative exponents:\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |