document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=662423>Question 662423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sonal's mother is thrice as old as Sonal.After 10 years,She will be just twice as old as her Daughter. what are their present age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412258 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To complete this \"find the age\" word problem, set up your equation with the following variables:<BR>\n" );
document.write( "x=mother<BR>\n" );
document.write( "y=sonal<BR>\n" );
document.write( "x=3y<BR>\n" );
document.write( "x=2y + 10<BR>\n" );
document.write( "Substitute x in the second equation<BR>\n" );
document.write( "3y = 2y +10<BR>\n" );
document.write( "y=10 years old for Sonal<BR>\n" );
document.write( "x=30 years old for Sonal's mother<BR>\n" );
document.write( "Verify your answer<BR>\n" );
document.write( "10(3)=30<BR>\n" );
document.write( "10+2(10)=30<BR>\n" );
document.write( "...............<BR>\n" );
document.write( "Delighted to help<BR>\n" );
document.write( "-Reading Boosters </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );