document.write( "Question 662425: hi there I am currently doing exponential equations and indices, which im understanding a few but unable to complete these. Can you assist?
\n" ); document.write( "1. 5^2x-6(5^x)+5=0
\n" ); document.write( " (5x)^2-6(5^x)+5=0
\n" ); document.write( " let 5x=y
\n" ); document.write( " y^2-6y+5=0
\n" ); document.write( "(this one i have started to work on but unable to finish)
\n" ); document.write( "2.4^x(5^2x)=10
\n" ); document.write( "3.7^x+1-2=2(7^x)+3
\n" ); document.write( "4.6(3^x-1)=3^4-3^x
\n" ); document.write( "I would greatly appreciate help thanks. \n" ); document.write( "

Algebra.Com's Answer #412238 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,previously Posted
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document.write( "1. 5^2x-6(5^x)+5=0
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document.write( " (5x)^2-6(5^x)+5=0
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document.write( " let     || Good work!
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document.write( " y^2-6y+5=0
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document.write( "factoring
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document.write( "(y-5)(y-1) = 0,  y = 5 0r y = 1  AND   x = 1  0r x = 1/5
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document.write( "As to the Remainder: the Idea is combining Like Terms...
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document.write( "2.4^x(5^2x)=10  ⇒ , x = 1/2 
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document.write( " 3.7^x+1-2=2(7^x)+3 ⇒ 7^x(7-2) = 5 ⇒ 7^x = 1,   x = 0 
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document.write( " 4. ⇒ 
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document.write( "   3^x (6*3^(-1)+1) = 3^x(2+1)= 81  ⇒  3^x = 27,    x = 3 \n" );
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