document.write( "Question 59830This question is from textbook Alegbra Concepts and Applications
\n" ); document.write( ": Solve the system of equations by substitution \r
\n" ); document.write( "\n" ); document.write( "y = x^2 + 2x - 2 \r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "y = 3x + 4
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Algebra.Com's Answer #41223 by ankor@dixie-net.com(22740)\"\" \"About 
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y = x^2 + 2x - 2
\n" ); document.write( "and
\n" ); document.write( "y = 3x + 4;
\n" ); document.write( ":
\n" ); document.write( "Just substitute (3x+4) for y in the 1st equation:
\n" ); document.write( "x^2 + 2x - 2 = y
\n" ); document.write( ":
\n" ); document.write( "x^2 + 2x - 2 = 3x + 4
\n" ); document.write( ":
\n" ); document.write( "Perform the necessay math operations to get everything on the left
\n" ); document.write( "x^2 + 2x - 3x - 2 - 4 = 0
\n" ); document.write( ":
\n" ); document.write( "x^2 - 1x - 6 = 0
\n" ); document.write( ":
\n" ); document.write( "Factor easily to:
\n" ); document.write( "(x - 3)(x + 2) = 0
\n" ); document.write( ":
\n" ); document.write( "x = +3 and x = -2
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check both solutions by substitution in both equations:
\n" ); document.write( "x = +3
\n" ); document.write( "3^2 + 2(3) - 2 = 13
\n" ); document.write( "and
\n" ); document.write( "3(3) + 4 = 13
\n" ); document.write( ":
\n" ); document.write( "x = -2
\n" ); document.write( "(-2)^2 + 2(-2) - 2 = -2
\n" ); document.write( "and
\n" ); document.write( "3(-2) + 4 = -2
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