document.write( "Question 59830This question is from textbook Alegbra Concepts and Applications
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document.write( ": Solve the system of equations by substitution \r
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document.write( "y = x^2 + 2x - 2 \r
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document.write( "and \r
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document.write( "y = 3x + 4
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Algebra.Com's Answer #41223 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! y = x^2 + 2x - 2 \n" ); document.write( "and \n" ); document.write( "y = 3x + 4; \n" ); document.write( ": \n" ); document.write( "Just substitute (3x+4) for y in the 1st equation: \n" ); document.write( "x^2 + 2x - 2 = y \n" ); document.write( ": \n" ); document.write( "x^2 + 2x - 2 = 3x + 4 \n" ); document.write( ": \n" ); document.write( "Perform the necessay math operations to get everything on the left \n" ); document.write( "x^2 + 2x - 3x - 2 - 4 = 0 \n" ); document.write( ": \n" ); document.write( "x^2 - 1x - 6 = 0 \n" ); document.write( ": \n" ); document.write( "Factor easily to: \n" ); document.write( "(x - 3)(x + 2) = 0 \n" ); document.write( ": \n" ); document.write( "x = +3 and x = -2 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check both solutions by substitution in both equations: \n" ); document.write( "x = +3 \n" ); document.write( "3^2 + 2(3) - 2 = 13 \n" ); document.write( "and \n" ); document.write( "3(3) + 4 = 13 \n" ); document.write( ": \n" ); document.write( "x = -2 \n" ); document.write( "(-2)^2 + 2(-2) - 2 = -2 \n" ); document.write( "and \n" ); document.write( "3(-2) + 4 = -2 \n" ); document.write( " \n" ); document.write( " |