document.write( "Question 662303: The first three terms of a geometric series are p-1, 2p, and 4p +6 respectively where p is a constant
\n" ); document.write( "(a) find the value of the constant p
\n" ); document.write( "(b) calculate the corresponding value of the common ratio
\n" ); document.write( "(c) Find the sum to ten terms of the series
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Algebra.Com's Answer #412190 by KMST(5328)\"\" \"About 
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The common ratio, is the ratio between consecutive terms in a geometric sequence, and it is constant, so
\n" ); document.write( "\"2p%2F%28p-1%29=%284p%2B6%29%2F2p\" --> \"4p%5E2=%28p-1%29%284p%2B6%29\" equating the cross-products
\n" ); document.write( "\"4p%5E2=%28p-1%29%284p%2B6%29\" --> \"4p%5E2=4p%5E2%2B2p-6\" --> \"0=2p-6\" --> \"2p=6\" --> \"highlight%28p=3%29\"
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\n" ); document.write( "The first three terms are
\n" ); document.write( "\"p-1=3-1=2\"
\n" ); document.write( "\"2p=2%2A3=6\" and
\n" ); document.write( "\"4p%2B6=4%2A3%2B6=12%2B6=18\"
\n" ); document.write( "The common ratio is \"6%2F2=highlight%283%29\"
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\n" ); document.write( "The sum of the first \"n\" terms of a geometric sequence with first term \"A\"
\n" ); document.write( "and common ratio \"r\" is
\n" ); document.write( "\"a%2A%28%28r%5En-1%29%2F%28r-1%29%29\"
\n" ); document.write( "In this case, it is \"2%2A%28%283%5E10-1%29%2F%283-1%29%29=2%2A%2859049-1%29%2F2=highlight%2859048%29\"\r
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