document.write( "Question 662382: perimeter of a traffic sign is 100 inches, its length is 8 inches longer than its width, find the dimensions of this sign.\r
\n" ); document.write( "\n" ); document.write( "Please show me the steps and not just the answer.
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Algebra.Com's Answer #412180 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "perimeter of a traffic sign is \"P=100in\", \r
\n" ); document.write( "\n" ); document.write( "its length \"L\" is \"8in\" longer than its width \"W\",=>..\"L=W%2B8in\"\r
\n" ); document.write( "\n" ); document.write( "...so, your traffic sign is a rectangle\r
\n" ); document.write( "\n" ); document.write( "and \"P=2%28L%2BW%29\" \r
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\n" ); document.write( "\n" ); document.write( "and \"100in=2%28L%2BW%29\" ........plug in \"L=W%2B8in\" and solve for \"W\"\r
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\n" ); document.write( "\n" ); document.write( "\"100in=2%28W%2B8in%2BW%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"cross%28100%2950in=cross%282%29%28W%2B8in%2BW%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"50in=2W%2B8in\"\r
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\n" ); document.write( "\n" ); document.write( "\"50in-8in=2W\"\r
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\n" ); document.write( "\n" ); document.write( "\"42in=2W\"\r
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\n" ); document.write( "\n" ); document.write( "\"42in%2F2=W\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28W=21in%29\"\r
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\n" ); document.write( "\n" ); document.write( "now find \"L\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=W%2B8in\"...plug in \"W=21in\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=21in%2B8in\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28L=29in%29\"\r
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