document.write( "Question 662228: if candle A has to burn for 8 seconds, candle B has to burn twice as long as candle C where as candle D has to burn 3 times less than candle B and the total time spent burning all candles is 30 seconds how long does candle B,C and D have to burn? \n" ); document.write( "
Algebra.Com's Answer #412151 by ankor@dixie-net.com(22740)\"\" \"About 
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if candle A has to burn for 8 seconds, candle B has to burn twice as long as candle C where as candle D has to burn 3 times less than candle B and the total time spent burning all candles is 30 seconds how long does candle B,C and D have to burn?
\n" ); document.write( ":
\n" ); document.write( "if candle A has to burn for 8 seconds,
\n" ); document.write( "a = 8
\n" ); document.write( " candle B has to burn twice as long as candle C
\n" ); document.write( "b = 2c
\n" ); document.write( "or
\n" ); document.write( "c = b/2
\n" ); document.write( ":
\n" ); document.write( "where as candle D has to burn 3 times less than candle B
\n" ); document.write( "d = (1/3)b
\n" ); document.write( ":
\n" ); document.write( "and the total time spent burning all candles is 30 seconds
\n" ); document.write( "a + b + c + d = 30
\n" ); document.write( "a = 8, therefore
\n" ); document.write( "b + c + d = 22 sec
\n" ); document.write( ":
\n" ); document.write( " how long does candle B,C and D have to burn?
\n" ); document.write( "replace c with b/2 and d with b/3
\n" ); document.write( "b + b/2 + b/3 = 22
\n" ); document.write( "multiply by 6, to get rid of the fractions
\n" ); document.write( "6b + 3b + 2b = 6(22)
\n" ); document.write( "11b = 132
\n" ); document.write( "b = 132/11
\n" ); document.write( "b = 12 min for candle b
\n" ); document.write( "then
\n" ); document.write( "c = 12/2 = 6 min for candle c
\n" ); document.write( "and
\n" ); document.write( "d = 12/3 = 4 min for candle d
\n" ); document.write( ":
\n" ); document.write( "Check this 8 + 12 + 6 + 4 = 30 min \n" ); document.write( "
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