document.write( "Question 59994: I need help working out these equations. My teacher made these problems up.
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document.write( "-8+t/3=7\r
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document.write( "4(x+3)=20\r
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document.write( "4y+3
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document.write( "_____ =9
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document.write( " 7 \n" );
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Algebra.Com's Answer #41207 by uma(370)![]() ![]() ![]() You can put this solution on YOUR website! 1. -8 + t/3 = 7 \n" ); document.write( "multiplying by 3 throughout, \n" ); document.write( "-8(3) +3(t/3) = 7(3) \n" ); document.write( "==> -24 + t = 21 \n" ); document.write( "==> -24 + 24 + t = 21 + 24 [adding 24 to both the sides] \n" ); document.write( "==> t = 45\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. 4(x+3) = 20 \n" ); document.write( "This can be worked out in 2 ways \n" ); document.write( "method 1: \n" ); document.write( "4(x+3) = 20 \n" ); document.write( "Dividing by 4 throughout, \n" ); document.write( "4(x+3)/4 = 20/4 \n" ); document.write( "==> x+3 = 5 \n" ); document.write( "==> x + 3 - 3 = 5 - 3[Subtracting 3 from both the sides] \n" ); document.write( "==> x = 2\r \n" ); document.write( "\n" ); document.write( "method 2: \n" ); document.write( "4(x+3) = 20 \n" ); document.write( "==> 4x + 12 = 20 [removing the parenthesis by multiplyingby 4] \n" ); document.write( "==> 4x + 12 - 12 = 20 - 12 \n" ); document.write( "==> 4x = 8 \n" ); document.write( "==> 4x/4 = 8/4 \n" ); document.write( "==> x = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3. (4y+3)/7= 9 \n" ); document.write( "Multiplying by 7 both the sides, \n" ); document.write( "4y + 3 = 63 \n" ); document.write( "==> 4y + 3 - 3 = 63 - 3[Subtracting 3 from both the sides] \n" ); document.write( "==> 4y = 60 \n" ); document.write( "==>4y/4 = 60/4 \n" ); document.write( "==> y = 15\r \n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( " |