document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59944>Question 59944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rental car costs $25 plus afixed charge per mile driven. The total chrge for 210 miles of use was $89. Write an equation for the cost,C(in dollars), in terms of the mile driven x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41206 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The total charge for 210 miles of use was $89.<BR>\n" );
document.write( "Let the fixed charge per mile driven be $p<BR>\n" );
document.write( "Then the equation is $25 + 210p = 89<BR>\n" );
document.write( "==> 210p = 89 - 25 [subtracting 25 from both the sides]<BR>\n" );
document.write( "==> 210p = 64<BR>\n" );
document.write( "==> 210p/210 = 64/210<BR>\n" );
document.write( "==> p = 0.31\r<BR>\n" );
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document.write( "so the fixed charge per mile driven = $0.31\r<BR>\n" );
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document.write( "The required equation for x miles driven would be <BR>\n" );
document.write( "C = 25 + 0.31x<BR>\n" );
document.write( " </SPAN>\n" );
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