document.write( "Question 59908: how to solve this problem? 5x-1<4 and x-2>-1 give solution set in interval and graph forms. for the compound inequality \n" ); document.write( "
Algebra.Com's Answer #41205 by tutorcecilia(2152)\"\" \"About 
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how to solve this problem? 5x-1<4 and x-2>-1 give solution set in interval and graph forms. for the compound inequality
\n" ); document.write( "5x-1<4
\n" ); document.write( "5x<4+1
\n" ); document.write( "5x<5
\n" ); document.write( "5x/5<5/5
\n" ); document.write( "x<1
\n" ); document.write( ".
\n" ); document.write( "and.
\n" ); document.write( "x-2>-1
\n" ); document.write( "x-2>-1
\n" ); document.write( "x-2+2>-1+2
\n" ); document.write( "x>1
\n" ); document.write( ".
\n" ); document.write( "Graphing:\r
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\n" ); document.write( "\n" ); document.write( "(negative infinity)===(0)===(1)===(2)===(3)===(positive infinity)\r
\n" ); document.write( "\n" ); document.write( "x<1 [Draw a dark arrow from 1 to negative infinity. Use an open circle over the number 1.
\n" ); document.write( ".
\n" ); document.write( "x>1 [Draw dark arrow from 1 to positive infiniyt. Keeping the circle over the number 1 opened.\r
\n" ); document.write( "\n" ); document.write( "Interval notation:
\n" ); document.write( "(-infinity, 1)(1, +infinity)
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