document.write( "Question 662215: How many different numbers of six digits can be formed from the digits 2,3,0,7,9,5 when repetition of digits is not allowed? \n" ); document.write( "

Algebra.Com's Answer #412029 by kevwill(135) $\"\"$ $\"About$

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Given that we are looking for 6-digit numbers, the first digit cannot be 0, so there are 5 possibilities for the first digit.
\n" ); document.write( "After using 1 digit, there are 5 remaining possibilities for the 2nd digit.
\n" ); document.write( "After using 2 digits, there are 4 remaining possibilities for the 3rd digit.
\n" ); document.write( "After using 3 digits, there are 3 remaining possibilities for the 4th digit.
\n" ); document.write( "After using 4 digits, there are 2 remaining possibilities for the 5th digit.
\n" ); document.write( "After using 5 digits, there is only 1 remaining possibility for the 6th digit.
\n" ); document.write( "So the total number of different 6-digit numbers that can be formed is:
\n" ); document.write( "5*5*4*3*2*1 = 600\r
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