document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=661227>Question 661227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length of one leg of a right triangle is x+2, and the length of the hypotenuse is x+3, where x>-2, what is the length of the other leg in terms of x?\r<BR>\n" );
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document.write( "I have difficulty setting the equation up, someone please explain! Much help is appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412007 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s = the length of the other leg<BR>\n" );
document.write( "Then using the Pythagorean theorem, we can write<BR>\n" );
document.write( "(x+3)^2 = (x+2)^2 + s^2<BR>\n" );
document.write( "s^2 = x^2 + 6x + 9 - x^2 - 4x - 4<BR>\n" );
document.write( "s^2 = 2x + 5<BR>\n" );
document.write( "So the length of the other side is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282x%2B5%29 ALIGN=MIDDLE  ALT=\"sqrt%282x%2B5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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