document.write( "Question 662125: If y varies inversely as the square of x, and y = 1/2 when x = 1, find y when x = 9. Thanks! \n" ); document.write( "
Algebra.Com's Answer #411972 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( " y = k/x^2
\n" ); document.write( " 1/2 = k/1, k = 1/2
\n" ); document.write( "when x = 9
\n" ); document.write( "y = \"%281%2F2%29%2F81+=+1%2F162\" \n" ); document.write( "
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