document.write( "Question 59829This question is from textbook Intermediate Algebra
\n" ); document.write( ": Solve each equation. If a solution is extraneous, so indicate.
\n" ); document.write( "(5)/(2z+z-3)-(2)/(2z+3)=(z+1)/(z-1)-(1) \n" ); document.write( "

Algebra.Com's Answer #41197 by funmath(2933) $\"\"$ $\"About$

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Solve each equation. If a solution is extraneous, so indicate.
\n" ); document.write( "(5)/(2z+z-3)***-(2)/(2z+3)=(z+1)/(z-1)-(1)
\n" ); document.write( "***I think you meant to type (2z^2+z-3)
\n" ); document.write( " $\"5%2F%282z%5E2%2Bz-3%29-2%2F%282z%2B3%29=%28z%2B1%29%2F%28z-1%29-1\"$ Factor the denominators.
\n" ); document.write( " $\"5%2F%28%282z%2B3%29%28z-1%29%29-2%2F%282z%2B3%29=%28z%2B1%29%2F%28z-1%29-1\"$
\n" ); document.write( "The LCD is(2z+3)(z-1), if you get a restriced value as an answer, it's extraneous.
\n" ); document.write( "2z+3=0--->2z=-3--->z=-3/2 Is a restricted value that will give you a 0 in the denominator.
\n" ); document.write( "z-1=0-->z=1 Is also a restricted value.
\n" ); document.write( "Multiply everything by the LCD:
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\n" ); document.write( " $\"5-2%28z-1%29=%28z%2B1%29%282z%2B3%29-1%282z%2B3%29%28z-1%29\"$
\n" ); document.write( " $\"5-2z%2B2=2z%5E2%2B3z%2B2z%2B3-2z%5E2-z%2B3\"$
\n" ); document.write( " $\"%285%2B2%29-2z=%282-2%29z%5E2%2B%283%2B2-1%29z%2B%283%2B3%29\"$
\n" ); document.write( " $\"7-2z=4z%2B6\"$
\n" ); document.write( " $\"7-6-2z%2B2z=4z%2B2z%2B6-6\"$
\n" ); document.write( " $\"1=6z\"$
\n" ); document.write( " $\"1%2F6=z\"$
\n" ); document.write( "That's not a restrted value so the solutions is: $\"highlight%28z=1%2F6%29\"$
\n" ); document.write( "Happy Calculating!!! \n" ); document.write( "

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