document.write( "Question 661979: The yearly production of a 5 foot orange tree is 35 pounds of oranges. A 12 foot tree produces 54 pounds.
\n" ); document.write( " What is the predicted production of an 18 foot tree?
\n" ); document.write( "What is the predicted production of an 20 foot tree?
\n" ); document.write( "What is the predicted height ( in feet ) of a tree that produces 88 pounds of oranges?
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Algebra.Com's Answer #411921 by KMST(5328)\"\" \"About 
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If the production, \"y\" of an orange tree varies linearly with its height, \"x\",
\n" ); document.write( "we can write the linear equation that describes it, knowing two (\"x\",\"y\") points.
\n" ); document.write( "\"The yearly production of a 5 foot orange tree is 35 pounds of oranges,\" gives us point (\"5\",\"35\").
\n" ); document.write( "\"A 12 foot tree produces 54 pounds,\" gives us point (\"12\",\"54\").
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\n" ); document.write( "I can see 3 ways to get the answer.
\n" ); document.write( "The expected way to solve the problem depends on what you are studying in class.
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\n" ); document.write( "CALCULATING SLOPE OF A LINE AND WRITING THE POINT-SLOPE FORM:
\n" ); document.write( "We can calculate the slope, \"m\" of the line:
\n" ); document.write( "\"m=%2854-35%29%2F%2812-5%29\" --> \"m=19%2F7\".
\n" ); document.write( "Then we can use that slope and the coordinates of one of the points to write the equation in point-slope form.
\n" ); document.write( "\"y-35=%2819%2F7%29%28x-5%29\"
\n" ); document.write( "From the point-slope form, we can go to the slope-intercept form, which will help answer the first 2 questions:
\n" ); document.write( "\"y-35=%2819%2F7%29%28x-5%29\"-->\"y-35=%2819%2F7%29x-5%2819%2F7%29\"-->\"y-35=%2819%2F7%29x-95%2F7\"-->\"y=%2819%2F7%29x-95%2F7%2B35\"-->\"y=%2819%2F7%29x-95%2F7%2B35\"-->\"y=%2819%2F7%29x%2B150%2F7\"
\n" ); document.write( "With a calculator, we can use the approximation \"y=2.714x%2B21.43\"
\n" ); document.write( "and get accurate enough results.
\n" ); document.write( "I'll stick with the fractions just in case you are expected to do that.
\n" ); document.write( "For the 18 foot tree, \"x=18\", so
\n" ); document.write( "\"y=%2819%2F7%29%2A18%2B150%2F7\"-->\"y=342%2F7%2B150%2F7\"-->\"y=492%2F7=70%262%2F7\"=about\"70.29\"=about\"70\" (rounding)
\n" ); document.write( "I assume the expected answer is \"70pounds\" rounding to whole numbers.
\n" ); document.write( "For the 20 foot tree,
\n" ); document.write( "\"x=20\" --> \"y=%2819%2F7%29%2A20%2B150%2F7\"-->\"y=380%2F7%2B150%2F7\"-->\"y=530%2F7=75%265%2F7\"=about\"75.71\"=about\"76\" (rounding)
\n" ); document.write( "I assume the expected answer is \"76pounds\" rounding to whole numbers.
\n" ); document.write( "For the 88 pound production, \"y=88\", so
\n" ); document.write( "\"88=%2819%2F7%29x%2B150%2F7\"-->\"88-150%2F7=%2819%2F7%29x\"-->\"616%2F7-150%2F7=%2819%2F7%29x\"-->\"466%2F7=%2819%2F7%29x\"
\n" ); document.write( "Multiplying both sides times \"7\":
\n" ); document.write( "\"466%2F7=%2819%2F7%29x\"-->\"466=19x\"-->\"x=466%2F19=24%2610%2F19\"=about\"24.53\"=about\"25\" (rounding)
\n" ); document.write( "I assume the expected answer is \"25feet\" rounding to whole numbers.
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\n" ); document.write( "SETTING UP A SYSTEM OF EQUATIONS TO FIND SLOPE AND INTERCEPT:
\n" ); document.write( "WE can find an equation of the form \"y=m%2Ax%2Bb\"
\n" ); document.write( "by substituting the coordinates for out 2 points and solving the system
\n" ); document.write( "\"system%2854=12m%2Bb%2C35=5m%2Bb%29\"
\n" ); document.write( "Solving the system of equations leads to
\n" ); document.write( "\"m=19%2F7\"=about\"2.714\" (rounding)
\n" ); document.write( "and \"b=150%2F7\"=about\"21.43\" (rounding)
\n" ); document.write( "From that point on, the calculations are the same as done above.
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\n" ); document.write( "USING A COMPUTER/CALCULATOR AS IF IT IS A STATISTICS PROBLEM
\n" ); document.write( "Using Excel functions in my computer, I can answer all 3 questions.
\n" ); document.write( "With A1=5, A2=12, B1=35, B2=54,
\n" ); document.write( "=FORECAST(18,B1:B2,A1:A2) gives me \"70.29\" or \"492%2F7\" or \"70%262%2F7\" pounds of oranges for an 18 foot tree.
\n" ); document.write( "=FORECAST(20,B1:B2,A1:A2) gives me \"75.71\" or \"530%2F7\" or \"75%265%2F7\" pounds of oranges for an 20 foot tree.
\n" ); document.write( "=FORECAST(88,A1:A2,B1:B2) gives me \"24.53\" feet for the height of a tree that would produce 88 pounds of oranges in a year.
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