document.write( "Question 662100: A college student earned $7200 during summer vacation working as a waiter at a popular restaurant. the student invested part of the money at 9% and the rest at 6%. if the student received a total of $492 in interest at the end of the year, how much was invested at 9%? \n" ); document.write( "
Algebra.Com's Answer #411920 by ReadingBoosters(3246)\"\" \"About 
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.09x + .06y = 492
\n" ); document.write( "x+y=7200
\n" ); document.write( "....................
\n" ); document.write( "Substitution
\n" ); document.write( ".09(7200-y) + .06y = 492
\n" ); document.write( "648 - .09y + .06y = 492
\n" ); document.write( "648 - 492 = .09y - .06y
\n" ); document.write( "156 = .03y
\n" ); document.write( "5200 = y = $ at 6%
\n" ); document.write( "7200 - 5200 = 2000 = x = $ at 9%
\n" ); document.write( "....................
\n" ); document.write( "$5200 at 6%
\n" ); document.write( "$2000 at 9%
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