document.write( "Question 661726: A fruitseller had some apples .he sells 40% of them and still has 420 apples.find the numnerrs of apples he had originally \n" ); document.write( "

Algebra.Com's Answer #411778 by colliefan(242) $\"\"$ $\"About$

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For all percentage problems, remember that the basic equation or formula is that the percentage is a ratio of some “part” divided by some “whole” or standard amount. That doesn't seem precise, but I think that language is helpful for all percentage problems. By part and whole, I mean that there will always be a number that is to be compared to another. \r
\n" ); document.write( "\n" ); document.write( "The basic formula or equation is always: Percentage = part/whole\r
\n" ); document.write( "\n" ); document.write( "In percentage problems, you are given 2 of the following 3 items:
\n" ); document.write( "the percentage
\n" ); document.write( "the part
\n" ); document.write( "the whole\r
\n" ); document.write( "\n" ); document.write( "Write the basic equation, substitute in what you know, and solve for what remains unknown.\r
\n" ); document.write( "\n" ); document.write( "In this case, you are given the percentage and the part because there was some larger amount of apples that the 420 is a part of. 402 is the amount of apples LEFT. The 40% is what was SOLD. The two must match. If 40% was sold, then 60% is what is left.\r
\n" ); document.write( "\n" ); document.write( "pct=part/whole
\n" ); document.write( "60% = 420/x
\n" ); document.write( "x*60% = 420/x*x
\n" ); document.write( "x*60% = 420*1/x*x
\n" ); document.write( "x*60% = 420*1
\n" ); document.write( "x*60% = 420
\n" ); document.write( "x*60%*1/60% = 420*1/60%
\n" ); document.write( "x*1 = 420*1/60%
\n" ); document.write( "x = 420/60%
\n" ); document.write( "x = 420/60%\r
\n" ); document.write( "\n" ); document.write( "x = 700 apples\r
\n" ); document.write( "\n" ); document.write( "Remember 60% = .60 \n" ); document.write( "

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