document.write( "Question 661586: The domain of the function: (1/ (sqrt (2x + 15)) and ( (x+2) / (x^2 - 225) ). I don't understand how to write it in interval notation. \n" ); document.write( "
Algebra.Com's Answer #411696 by lwsshak3(11628)\"\" \"About 
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The domain of the function: (1/ (sqrt (2x + 15)) and ( (x+2) / (x^2 - 225) ). I don't understand how to write it in interval notation.
\n" ); document.write( "**
\n" ); document.write( "(1/ (sqrt (2x + 15))
\n" ); document.write( "(1/√(2x+15)
\n" ); document.write( "2 restrictions apply here:
\n" ); document.write( "radican≥0
\n" ); document.write( "and
\n" ); document.write( "denominator≠0
\n" ); document.write( "..
\n" ); document.write( "for radican:
\n" ); document.write( "2x+15>0
\n" ); document.write( "2x>-15
\n" ); document.write( "x>-15/2
\n" ); document.write( "..
\n" ); document.write( "for denominator:
\n" ); document.write( "2x+15=0
\n" ); document.write( "2x=-15
\n" ); document.write( "x≠-15/2
\n" ); document.write( "domain: (-15/2,∞)
\n" ); document.write( "..
\n" ); document.write( "( (x+2) / (x^2 - 225) )
\n" ); document.write( "(x+2)/(x^2-225)
\n" ); document.write( "(x+2)/(x^2-15^2)
\n" ); document.write( "(x+2)/(x+15)(x-15)
\n" ); document.write( "one restriction applies here: denominator≠0
\n" ); document.write( "(x+15)(x-15)=0
\n" ); document.write( "x≠15
\n" ); document.write( "and
\n" ); document.write( "x≠-15
\n" ); document.write( "domain: (-∞,-15) U (-15,15) U (15,∞)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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