document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=661483>Question 661483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are 12 liters of 60% acid solution. How much must be drained and replaced with pure acid to get a final strength of 75%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411694 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are 12 liters of 60% acid solution. How much must be drained and replaced with pure acid to get a final strength of 75%?<BR>\n" );
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document.write( "let x=amt of 60% acid solution to be drained and replaced with pure acid.<BR>\n" );
document.write( "12-x=amt of 60% acid solution remaining in container<BR>\n" );
document.write( "..<BR>\n" );
document.write( "60%(12-x)+100%x=75%*12<BR>\n" );
document.write( "7.2-.6x+x=9<BR>\n" );
document.write( ".4x=1.8<BR>\n" );
document.write( "x=4.5<BR>\n" );
document.write( "amt of 60% acid solution to be drained and replaced with pure acid=4.5 liters </SPAN>\n" );
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