document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=661539>Question 661539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tank holds 95 liters of a chemical solution. Currently, the solution has a strength of 20%. How much of this should be drained and replaced with a 65% solution to get a final strength of 50%? Could you write the original equation also. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411690 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A tank holds 95 liters of a chemical solution. Currently, the solution has a strength of 20%. How much of this should be drained and replaced with a 65% solution to get a final strength of 50%? Could you write the original equation also.<BR>\n" );
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document.write( "let x=amt of 20% solution to be drained and replaced with 65% solution.<BR>\n" );
document.write( "95-x=amt of 20% solution remaining in tank.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "20%(95-x)+65%x=50%*95<BR>\n" );
document.write( "19-.2x+.65x=47.5<BR>\n" );
document.write( ".45x=28.5<BR>\n" );
document.write( "x=63+1/3 liters<BR>\n" );
document.write( "amt of 20% solution to be drained and replaced with 65% solution=63+1/3 liters </SPAN>\n" );
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