document.write( "Question 661489: the length of a rectangle is 18cm more than the width . a second rectangle is 6cm shorter and 3cm wider than the first and has a perimeter of 126cm. find the dimensions of each rectangle. \n" ); document.write( "
Algebra.Com's Answer #411648 by ReadingBoosters(3246)\"\" \"About 
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rectangle 1
\n" ); document.write( "x = l = 18 + w
\n" ); document.write( "y = w
\n" ); document.write( "rectangle 2
\n" ); document.write( "l = x - 6
\n" ); document.write( "w = y + 3
\n" ); document.write( "p = 2l+2w=126
\n" ); document.write( "Lots of substitutions!
\n" ); document.write( "Using rectangle 2, which is given in terms of rectangle 1
\n" ); document.write( "p = 2(x-6)+2(y+3)=126
\n" ); document.write( "p = 2((18 + w)-6) + 2(w + 3) = 126
\n" ); document.write( "Distribute the 2s
\n" ); document.write( "36 + 2w - 12 + 2w + 6 = 126
\n" ); document.write( "Combine like terms
\n" ); document.write( "4w + 36 - 12 + 6 = 126
\n" ); document.write( "4w +30 = 126
\n" ); document.write( "4w = 96
\n" ); document.write( "w=24=width of rectangle 1
\n" ); document.write( "Rectangle 1
\n" ); document.write( "l = 18 + 24 = 42cm length
\n" ); document.write( "w = 24 cm width
\n" ); document.write( "Rectangle 2
\n" ); document.write( "l = 42 - 6 = 36 cm length
\n" ); document.write( "w = 24 + 3 = 27 cm width\r
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