document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=661495>Question 661495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 less than twice the width the perimeter is 30cm what is the length and width?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411639 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411639\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = 2(l+w) = 2l+2w = 30<BR>\n" );
document.write( "l = 2w - 3<BR>\n" );
document.write( "Substitute l into the perimeter equation<BR>\n" );
document.write( "2(2w-3)+2w = 30<BR>\n" );
document.write( "Distribute the 2<BR>\n" );
document.write( "4w - 6 + 2w = 30<BR>\n" );
document.write( "Combine like terms<BR>\n" );
document.write( "6w = 30 + 6<BR>\n" );
document.write( "6w=36<BR>\n" );
document.write( "6w/6 = 36/6<BR>\n" );
document.write( "w = 6<BR>\n" );
document.write( "l = 2(6) - = 9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );