document.write( "Question 661498: hello can you please help me solve,\" rectangular garden has a perimeter 66 ft and area 216 ftsquared. how can i find the dimensions of the garden.\" I know that P=2L +2W and Area= LxW can i do L times W = 216 ft squared and is L=2w so is it 2w times w = 216 AND THEN I AM STUCK...please help! \n" ); document.write( "
Algebra.Com's Answer #411638 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! p = 2l+2w=66 or l = (66-2w)/2 \n" ); document.write( "a = lw = 216\r \n" ); document.write( "\n" ); document.write( "using area \n" ); document.write( "[(66 - 2w)/2](w) = 216 \n" ); document.write( "Multiply both sides by 2 \n" ); document.write( "(66-2w)(w) = 216(2) \n" ); document.write( "66w - 2w^2 = 432 \n" ); document.write( "-2w^2 + 66w - 432 = 0 \n" ); document.write( "-2(w^2 - 33w + 216)=0 \n" ); document.write( "divide both sides by -2 \n" ); document.write( "w^2 - 33w + 216 = 0 \n" ); document.write( "(w - )(w - ) mixed signs due to + 216, but - 33 \n" ); document.write( "Look for multiple of 216 that add to make 33: 24,9 \n" ); document.write( "(w-24)(w- 9) \n" ); document.write( "w = 24, w = 9 \n" ); document.write( "width or length is 24ft \n" ); document.write( "width or length is 9ft \n" ); document.write( " |