document.write( "Question 59955: How do I find the solution set, given the replacement set:\r
\n" ); document.write( "\n" ); document.write( "5x + 2y = 5 [(2, -2), (2, -7), (5, -4), (3, -5)}
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Algebra.Com's Answer #41161 by praseena(37)\"\" \"About 
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5x + 2y = 5 \r
\n" ); document.write( "\n" ); document.write( "The replacement set is [(2, -2), (2, -7), (5, -4), (3, -5)}\r
\n" ); document.write( "\n" ); document.write( "At first input the first set of values, that is (2,-2) in the given equation,\r
\n" ); document.write( "\n" ); document.write( "==> 5*2 + 2*-2 = 10 + -4 = 6\r
\n" ); document.write( "\n" ); document.write( "That is the value we got while substituting in the left side of the given equation is not same as the right side.
\n" ); document.write( " So (2,-2) is not a solution for the given equation.\r
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\n" ); document.write( "Now substitute the second pair of values in the given equation.\r
\n" ); document.write( "\n" ); document.write( "==> 5 * 2 + 2 * -7 = 10 + -14 = -4, which is again not equal to 5\r
\n" ); document.write( "\n" ); document.write( "so (2,-7) is not a solution\r
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\n" ); document.write( "\n" ); document.write( "Now take (5,-4)\r
\n" ); document.write( "\n" ); document.write( "==> 5 * 5 + 2 * -4 = 25 + -8 = 16, which is again not equal to 5
\n" ); document.write( "so this is also not a solution for the given equation.\r
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\n" ); document.write( "Now take the pair of values, (3,-5)\r
\n" ); document.write( "\n" ); document.write( "==> 5*3 + 2*-5 = 15 + -10 = 5, which is equal to the right side. \r
\n" ); document.write( "\n" ); document.write( "so (3,-5) is the solution set of the given equation.\r
\n" ); document.write( "\n" ); document.write( "O.K
\n" ); document.write( "BYE.
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