document.write( "Question 661444: 2x squared minus 5y plus 3, where x=1/2 and y=-3/4 \n" ); document.write( "
Algebra.Com's Answer #411609 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2x squared minus 5y plus 3, where x=1/2 and y=-3/4
\n" ); document.write( "--------
\n" ); document.write( "2x^2 - 5y + 3
\n" ); document.write( "----
\n" ); document.write( "Substitute to evaluate:
\n" ); document.write( "2(1/2)^2 - 5(-3/4) + 3
\n" ); document.write( "-----
\n" ); document.write( "1/2 + 15/4 + 3
\n" ); document.write( "-----
\n" ); document.write( "2/4 + 15/4 + 12/4
\n" ); document.write( "-----
\n" ); document.write( "= 29/4
\n" ); document.write( "===========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===========
\n" ); document.write( "
\n" );