document.write( "Question 661336: I'm trying to help my daughter with her algebra homework and want to make sure I've done the problem correctly before I do?!?\r
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document.write( "a/7 + 5/7 = 2/7\r
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document.write( "My answer is a = -3\r
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document.write( "Am I correct? \n" );
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Algebra.Com's Answer #411595 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I'm trying to help my daughter with her algebra homework and want to make sure I've done the problem correctly before I do?!?\r \n" ); document.write( "\n" ); document.write( "a/7 + 5/7 = 2/7\r \n" ); document.write( "\n" ); document.write( "My answer is a = -3\r \n" ); document.write( "\n" ); document.write( "Am I correct?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Yes, you are!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In order to determine if your solution to an equation is correct, you just have to substitute the value of each variable into the original equation(s), and see if that/those value(s) makes the equation(s) true. Hence,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |