document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=661395>Question 661395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular field is 660 yards. If the width is 20 yards less than the length, than what is the length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411592 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = 2(l+w) = 2l+2w = 660<BR>\n" );
document.write( "w= l - 20<BR>\n" );
document.write( "Substitute w into the equation<BR>\n" );
document.write( "660 = 2l + 2(l-20)<BR>\n" );
document.write( "660 = 2l + 2l - 40<BR>\n" );
document.write( "660 = 4l - 40<BR>\n" );
document.write( "620 = 4l<BR>\n" );
document.write( "155 yd = length<BR>\n" );
document.write( " </SPAN>\n" );
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