document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59953>Question 59953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 times another.  If the sum of their reciprocals is 4/21, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41159 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let \"x\" and \"y\" be two numbers. \r<BR>\n" );
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document.write( "Given that one is thrice the other.\r<BR>\n" );
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document.write( "Hence x = 3y.\r<BR>\n" );
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document.write( "Given that the sum of their reciprocals equals 4/21 \r<BR>\n" );
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document.write( "Thus, the equation is: \r<BR>\n" );
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document.write( "1/(3y + y) = 4/21\r<BR>\n" );
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document.write( "1/4y = 4/21 \r<BR>\n" );
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document.write( "16y = 21\r<BR>\n" );
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document.write( "y = 21/16 \r<BR>\n" );
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document.write( "Therefore,  x = 3y \r<BR>\n" );
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document.write( "x = 3(21/16)  \r<BR>\n" );
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document.write( "x = 63/16 \r<BR>\n" );
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document.write( "Thus the two numbers are x = 63/16 and y = 21/16 \r<BR>\n" );
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document.write( " </SPAN>\n" );
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