document.write( "Question 661236: at the beinning of a walk jack roberto and juanita are 5.5 miles apart. If they leave at the same time and walk in the same direction, roberto over takes juanita in 11 hours. If they walk toward eachother, they meet in 1 hour. what are their speeds? \n" ); document.write( "
Algebra.Com's Answer #411563 by josmiceli(19441)\"\" \"About 
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It is possible to tell from the problem who walks faster
\n" ); document.write( "Walking in the same direction, roberto over takes juanita.
\n" ); document.write( "If Roberto walked slower than her, he would never catch her
\n" ); document.write( "so he is the faster walker
\n" ); document.write( "Let \"+r+\" = his speed in mi/hr
\n" ); document.write( "Let \"+j+\" = her speed in mi/hr
\n" ); document.write( "-------------------
\n" ); document.write( "I can think of Juanita as standing still and Roberto as
\n" ); document.write( "approaching at the difference of their speeds
\n" ); document.write( "(1) \"+5.5+=+%28+r+-+j+%29%2A11+\"
\n" ); document.write( "-------------------
\n" ); document.write( "Walking toward each other, think of Juanita
\n" ); document.write( "as standing still and add their speeds
\n" ); document.write( "(2) \"+5.5+=+%28+r+%2B+j+%29%2A1+\"
\n" ); document.write( "---------------------
\n" ); document.write( "(1) \"+5.5+=+11r+-+11j+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+5.5+=+r+%2B+j+\"
\n" ); document.write( "(2) \"+j+=+5.5+-+r+\"
\n" ); document.write( "substitute (2) into (1)
\n" ); document.write( "(1) \"+5.5+=+11r+-+11%2A%28+5.5+-+r+%29+\"
\n" ); document.write( "(1) \"+5.5+=+11r+-+60.5+%2B+11r+\"
\n" ); document.write( "(1) \"+22r+=+60.5+%2B+5.5+\"
\n" ); document.write( "(1) \"+22r+=+66+\"
\n" ); document.write( "(1) \"+r+=+3+\"
\n" ); document.write( "and, since
\n" ); document.write( "(2) \"+j+=+5.5+-+r+\"
\n" ); document.write( "(2) \"+j+=+5.5+-+3+\"
\n" ); document.write( "(2) \"+j+=+2.5+\"
\n" ); document.write( "3 mi/hr is his speed in mi/hr
\n" ); document.write( "2.5 mi/hr is her speed in mi/hr
\n" ); document.write( "check:
\n" ); document.write( "In 11 hrs, she walks \"+d+=+2.5%2A11+\"
\n" ); document.write( "\"+d+=+27.5+\" mi
\n" ); document.write( "In 11 hrs, he walks \"+d+=+3%2A11+=+33+\"
\n" ); document.write( "\"+33+-+27.5+=+5.5+\", so he makes up
\n" ); document.write( "the 5.5 mi difference
\n" ); document.write( "OK\r
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