document.write( "Question 658776: Rate 1 $42 plus $.12 mile
\n" ); document.write( "Rate 2 $84 plus .06 mile
\n" ); document.write( "How many miles must one drive to pay less than Rate 2\r
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\n" ); document.write( "\n" ); document.write( "how do I work this problem
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Algebra.Com's Answer #411554 by Jazleen(5)\"\" \"About 
You can put this solution on YOUR website!
step:\r
\n" ); document.write( "\n" ); document.write( "1) \"+rate+1+%3C+rate+2+\"\r
\n" ); document.write( "\n" ); document.write( "2) let x be the # of miles: \"+42+%2B+.12x+%3C+84+%2B+.06x\"\r
\n" ); document.write( "\n" ); document.write( "3) make .12 and .06 whole numbers by moving ALL decimals (including 42 and 84)two spaces to the right: \"+4200+%2B+12x+%3C+8400+%2B+6x+\"\r
\n" ); document.write( "\n" ); document.write( "4) subtract 6x from both sides: \"+4200+%2B+12x+-6x+%3C+8400+%2B+6x+-+6x+\"\r
\n" ); document.write( "\n" ); document.write( "5)\"+4200+%2B+6x+%3C+8400+\"\r
\n" ); document.write( "\n" ); document.write( "6) subtract 4200 from both sides: \"4200+-+4200+%2B+6x+%3C+8400+-+4200\"\r
\n" ); document.write( "\n" ); document.write( "7) \"6x+%3C+4200\"\r
\n" ); document.write( "\n" ); document.write( "8) devide both sides by 6 to get x by itself: \"+6x%2F6+%3C+4200%2F6+\"\r
\n" ); document.write( "\n" ); document.write( "9) answer is greater than 700 miles \"+x%3C700+\"
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