document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=661099>Question 661099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the solution set of (x + 2)2 = 36.\r<BR>\n" );
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document.write( "{6, -8}<BR>\n" );
document.write( "{4, -8}<BR>\n" );
document.write( "{4, -6} </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411493 by </B><A HREF=/tutors/aboutme.mpl?userid=colliefan><B>colliefan(242)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=colliefan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What you need to remember is that a positive number and it's additive inverse both give you the same number when they are squared. Eg;  4 and -4 both give you 16 when they are squared.\r<BR>\n" );
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document.write( "The square root of 36 is 6. The solutions for x then must be either 6 squared or -6 squared. \r<BR>\n" );
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document.write( "x+2=6   and   x+2=-6   then are equations that give the two solutions.\r<BR>\n" );
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document.write( "x+2=6<BR>\n" );
document.write( "x=4\r<BR>\n" );
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document.write( "x+2=-6<BR>\n" );
document.write( "x=-8\r<BR>\n" );
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document.write( "(4,-8) </SPAN>\n" );
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