document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59951>Question 59951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me how to Write the equation in terms of y. \r<BR>\n" );
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document.write( "3X = 5 - y and 6x + 2y = 10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41149 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given equations are: \r<BR>\n" );
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document.write( "3x = 5 - y   and    6x + 2y = 10 \r<BR>\n" );
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document.write( "3x = 5 - y \r<BR>\n" );
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document.write( "Adding y - 3x  from both sides of equation (1), we get: \r<BR>\n" );
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document.write( "y = 5 - 3x  This is the equation in terms of y. \r<BR>\n" );
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document.write( "6x + 2y = 10 \r<BR>\n" );
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document.write( "subtracting 6x from both sides of the above equation, we get: \r<BR>\n" );
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document.write( "2y = 10 - 6x \r<BR>\n" );
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document.write( "Divide the entire equation by 2\r<BR>\n" );
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document.write( "y = 5 - 3x \r<BR>\n" );
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document.write( "This is the equation in terms of y \r<BR>\n" );
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document.write( " </SPAN>\n" );
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