document.write( "Question 661052: I have a problem where on a graph, x= -5, -4, -3, -2 and y= 2, 0, -2, -4. How do I write an equation for y='s when the difference between y & x is not constant? \n" ); document.write( "
Algebra.Com's Answer #411474 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "It's not the difference between the y & x-values we need to explore...
\n" ); document.write( "1st***We need to use the points and determine the behavior of the
\n" ); document.write( "'change' that occurs moving from one to another.
\n" ); document.write( "(change in y) / (change in x ) determines the slope of this Line
\n" ); document.write( " x= -5, -4, -3, -2 and y= 2, 0, -2, -4
\n" ); document.write( "Points:
\n" ); document.write( "(-5,2)
\n" ); document.write( "(-4,0) \"+m+=+%282-0%29%2F%28-5-%28-4%29%29+=+2%2F-1+=+-2\"
\n" ); document.write( "(-3,-2) m = 2/-1 = -2
\n" ); document.write( "(-2,-4) m = 2/-1 = 2\r
\n" ); document.write( "\n" ); document.write( "Using the standard slope-intercept form for an equation of a line y = mx + b
\n" ); document.write( " where m is the slope and b the y-intercept.
\n" ); document.write( " y = -2x+ b || Using (x,y) ordered pair (-4,0) to solve for b
\n" ); document.write( "\"+0+=+-2%2A-4+%2B+b\"
\n" ); document.write( " 8 = b
\n" ); document.write( " y = -2x+ 8 \n" ); document.write( "
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