document.write( "Question 661014: solve using elimination or substitution\r
\n" ); document.write( "\n" ); document.write( "5/3 d - 3/5 g = 61\r
\n" ); document.write( "\n" ); document.write( "3/5 d + 5/3 g = -91\r
\n" ); document.write( "\n" ); document.write( "Having trouble clearing the fractions. I used 15 as the LCD and got\r
\n" ); document.write( "\n" ); document.write( "25d -9g =915
\n" ); document.write( "9d + 25g = -1365\r
\n" ); document.write( "\n" ); document.write( "but then I get weird numbers from there... \n" ); document.write( "

Algebra.Com's Answer #411443 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "25d -  9g =   915\r\n" );
document.write( " 9d + 25g = -1365\r\n" );
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document.write( "Multiply the first equation through by 25\r\n" );
document.write( "Multiply the second equation through by 9\r\n" );
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document.write( "625d - 225g =  22875\r\n" );
document.write( " 81d + 225g = -12285\r\n" );
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document.write( "Add them term by term and get\r\n" );
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document.write( "706d        =  10590\r\n" );
document.write( "          d = 15\r\n" );
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document.write( "Substitute in \r\n" );
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document.write( "   9d + 25g = -1365\r\n" );
document.write( "9(15) + 25g = -1365\r\n" );
document.write( "  135 + 25g = -1365\r\n" );
document.write( "        25g = -1500\r\n" );
document.write( "          g = -60\r\n" );
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document.write( "Edwin

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