document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=566545>Question 566545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tickets for the father and son breakfast were 2 dollars for fathers and 1.50 dollars for sons. If a total of of 75 tickets were sold for 127.50 dollars, how many fathers and how many sons attended the breakfast?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411441 by </B><A HREF=/tutors/aboutme.mpl?userid=radium><B>radium(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=radium><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=radium><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411441\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This can be solved with 1 variable as well!<BR>\n" );
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document.write( "The equation<BR>\n" );
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document.write( "1.5x + 2.00(75 - x) = 127.5<BR>\n" );
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document.write( "We let x represent the number of sons tickets. We know that that the number of father tickets must be (75 - x). We know that the sons tickets are $1.50 each and the fathers tickets are $2.00 each. So we arrange our equation accordingly.<BR>\n" );
document.write( "1.5x + 2.00(75 - x) = 127.5.<BR>\n" );
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document.write( "Using the distributive property we get: 1.5x + 150 - 2x = 127.5\r<BR>\n" );
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document.write( "Combining like terms gives us: -.5x=-22.5\r<BR>\n" );
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document.write( "Dividing both sides by -.5 gives us: x = 45\r<BR>\n" );
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document.write( "45 of sons tickets were sold, to find the amount of fathers we simply subtract 45 from 75 which gives us 30, the amount of fathers tickets sold. </SPAN>\n" );
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