document.write( "Question 660257: point of intersection 5x+4y-32=0 and x^2+y^2=25\r
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Algebra.Com's Answer #411438 by lwsshak3(11628) $\"\"$ $\"About$

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point of intersection
\n" ); document.write( "x^2+y^2=25
\n" ); document.write( "y^2=25-x^2
\n" ); document.write( "y=√(25-x^2)
\n" ); document.write( "..
\n" ); document.write( "5x+4y-32=0
\n" ); document.write( "4√(25-x^2)=32-5x
\n" ); document.write( "square both sides
\n" ); document.write( "16(25-x^2)=1024-320x+25x^2
\n" ); document.write( "400-16x^2=1024-320x+25x^2
\n" ); document.write( "41x^2-320x+624=0
\n" ); document.write( "solve by following quadratic formula:
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "a=41, b=-320, c=624
\n" ); document.write( "ans:
\n" ); document.write( "x=4
\n" ); document.write( "y=√(25-x^2)=√(25-16)=√9=3
\n" ); document.write( "or
\n" ); document.write( "x≈3.805
\n" ); document.write( "y=√(25-x^2)=√(25-14.478)=√10.522≈3.244
\n" ); document.write( "2 points of intersection: (4,3) and (3.805,3.244)
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