document.write( "Question 660804: please help me solve this problem. A chemist has two solutions of HNO3. One has 40% concentration and the other has 25% concentration. How many liters of each solution must be mixed to ob tain 57 liters of a 26% solution? \n" ); document.write( "
Algebra.Com's Answer #411364 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = liters of 40% solution needed
\n" ); document.write( "Let \"+b+\" = liters of 25% solution needed
\n" ); document.write( "\"+.4a+\" = liters of HN03 in 40% solution
\n" ); document.write( "\"+.25b+\" = liters of HN03 in 25% solution
\n" ); document.write( "------------------------------------
\n" ); document.write( "(1) \"+%28+.4a+%2B+.25b+%29+%2F+57+=+.26+\"
\n" ); document.write( "(2) \"+a+%2B+b+=+57+\"
\n" ); document.write( "-----------------
\n" ); document.write( "(1) \"+.4a+%2B+.25b+=+.26%2A57+\"
\n" ); document.write( "(1) \"+.4a+%2B+.25b+=+14.82+\"
\n" ); document.write( "(1) \"+40a+%2B+25b+=+1482+\"
\n" ); document.write( "Multiply both sides of (2) by \"+25+\"
\n" ); document.write( "and subtract (2) from (1)
\n" ); document.write( "(1) \"+40a+%2B+25b+=+1482+\"
\n" ); document.write( "(2) \"+-25a+-+25b+=+-1425+\"
\n" ); document.write( "\"+15a+=+57+\"
\n" ); document.write( "\"+a+=+3.8+\"
\n" ); document.write( "and, since
\n" ); document.write( "(2) \"+a+%2B+b+=+57+\"
\n" ); document.write( "(2) \"+3.8+%2B+b+=+57+\"
\n" ); document.write( "(2) \"+b+=+53.2+\"
\n" ); document.write( "3.8 liters of 40% solution are needed
\n" ); document.write( "53.2 liters of 25% solution are needed
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+%28+.4a+%2B+.25b+%29+%2F+57+=+.26+\"
\n" ); document.write( "(1) \"+%28+.4%2A3.8+%2B+.25%2A53.2+%29+%2F+57+=+.26+\"
\n" ); document.write( "(1) \"+%28+1.52+%2B+13.3+%29+%2F+57+=+.26+\"
\n" ); document.write( "(1) \"+14.82+=+.26%2A57+\"
\n" ); document.write( "(1) \"+14.82+=+14.82+\"
\n" ); document.write( "OK
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